(100x-0.5x^2)-(60x+300)=2500

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Solution for (100x-0.5x^2)-(60x+300)=2500 equation: 



(100x-0.5x^2)-(60x+300)=2500

We move all terms to the left:

(100x-0.5x^2)-(60x+300)-(2500)=0

We get rid of parentheses

-0.5x^2+100x-60x-300-2500=0

We add all the numbers together, and all the variables

-0.5x^2+40x-2800=0

a = -0.5; b = 40; c = -2800;
Δ = b2-4ac
Δ = 402-4·(-0.5)·(-2800)
Δ = -4000
Delta is less than zero, so there is no solution for the equation

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